There were three Medieval kingdoms on the shores of a lake. There was an<BR>island in the middle of the lake, which the kingdoms had been fighting<BR>over for years. Finally, the three kings decided that they would send<BR>their knights out to do battle, and the winner would take the island.<P>The night before the battle, the knights and their squires pitched camp<BR>and readied themselves for the fight. The first kingdom had 12 knights,<BR>and each knight had 5 squires, all of whom were busily polishing armor,<BR>brushing horses, and cooking food. The second kingdom had 20 knights,<BR>and each knight had 10 squires. Everyone at that camp was also busy<BR>preparing for battle. At the camp of the third kingdom, there was only<BR>one knight, with his squire. This squire took a large pot and hung it<BR>from a looped rope in a tall tree. He busied himself preparing the meal,<BR>while the knight polished his own armor.<P>When the hour of the battle came, the three kingdoms sent their squires<BR>out to fight (this was too trivial a matter for the knights to join in).<BR>The battle raged, and when the dust cleared, the only person left was<BR>the lone squire from the third kingdom, having defeated the squires from<BR>the other two kingdoms.<P>Thus proving that the squire of the high pot and noose is equal to the<BR>sum of the squires of the other two sides.